An electric bulb is rated 200v-100w. What is its resistance. 5 such bulbs burn for 4hers what is the electrical energy consumed. Calculate the cost if the price is 50p/unit (from ohms triangle )
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we know that for an electric appliance P = V² /R or resistance will be given as R = V² / P
now, here P = 100 W V = 200 volts
so, R = 200² / 100= 40000 / 100
thus, resistance of the bulb is R = 400 Ω
now, electric energy consumed will be E = number of units x power of each unit x time = n x P x t
heren = 5 P = 100 W t = 4 hours so, E = 5 x 100 x 4
thus, E = 2000 Wh = 2 kWh
the total cost of electricity = total unit of energy consumed x cost per unit = 2kWh x 0.5 Rs/kWh thus, total cost (daily) = Rs. 1 and monthly cost = total daily cost x number of days in month = Rs. 1 x 30 days or monthly cost = Rs. 30
now, here P = 100 W V = 200 volts
so, R = 200² / 100= 40000 / 100
thus, resistance of the bulb is R = 400 Ω
now, electric energy consumed will be E = number of units x power of each unit x time = n x P x t
heren = 5 P = 100 W t = 4 hours so, E = 5 x 100 x 4
thus, E = 2000 Wh = 2 kWh
the total cost of electricity = total unit of energy consumed x cost per unit = 2kWh x 0.5 Rs/kWh thus, total cost (daily) = Rs. 1 and monthly cost = total daily cost x number of days in month = Rs. 1 x 30 days or monthly cost = Rs. 30
adhilaadhila:
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