An electric bulb is rated 220 v and 100 W when it is operated in 110v the power consumed will be
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P = V2/R If V = 220 V we have
100 W = 2202/RR = 2202/100 Ω = 484 Ω. This is the resistance of the bulb.
When V = 110 V, power consumed = V2/R = 1102 /484 = 25 W
100 W = 2202/RR = 2202/100 Ω = 484 Ω. This is the resistance of the bulb.
When V = 110 V, power consumed = V2/R = 1102 /484 = 25 W
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