An electric bulb is rated 220V , 110W. When it is operated on 110V , the power consumed will be
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****Hey mate****
We know that,
P = V^2/R
If V = 220 V we have
100 W = 220^2/R
R = 220^2/100 Ω = 484 Ω. This is the resistance of the bulb.
When V = 110 V, power consumed = V^2/R = 110^2/484 = 25 W.
So, 25 W power is consumed when it is operated on 110 W.
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