Question

An electric bulb is rated 220V,480W .It is then connected across a a 440V supply. Calculate the Power dissipated by the electric bulb.
Answer please

Answer 1

We know P=V²/R ------ 1

Therefore, R=V²/P ------- 2

Therefore resistance of the bulb is.....

R=V²/P=(220*220)/480

Now the voltage supplied across the circuit is 440 V.

Therefore the power dissipated is....

P=V²/R=(440*440*480)/(220*220)

=4*480=1920 W

Answer 2

Answer:

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Explanation:

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