An electric bulb is rated 220v and 100 w.Power consumed by when 110 volt is
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Power=100W.........given
P.D=220V.......given
Therefore,
P=V²/R
So, R=V²/P
So, R=(220)²/100
So, R=48400/100
So, R=484ohm
Now Resistance is same
So, now
R=484ohm
V=110
Therefore
P=V²/R
So, P=(110)²/484
So, P=12100/484
So, P=25W
Therefore Power at 110V is 25watt
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