An electric bulb is rated 220V and 40W .when it is operated on 110 V.The power consumed will be
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Hi friend here is your answer.
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P=V^2/r
r=V^2/P=(220)^2/40
r= resistance of the bulb.
Now
P=V^2/r=(110)^2/[(220)^2/40]
Solve it to get the ans.
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