Question

an electric bulb is rated at 200V ,100W .what is the resistance?if 5 such bulbs burn for 4 hours .what is the electrical energy consumed?calculate the cost if ,the rate is 50 paise per unit.

Answer 1

• According to the problem

• V=200V

• Power= 100 watt

• According to the formula

• P=VI

• Therefore I= P/V

• It means that when power is divided by voltage, it gives current

• Hence placing the value

• We get I= 100/200=0.5 ampere

• In fact resistance =200/0.5 = 400 OHM

• Energy spent by the bulb in one hour=100 watt

• Energy utilized in 5 bulbs in one hour= 5*100=5 KW

• Cost of electricity= 5*0.46=2.30Rs

Answer 2

$\huge\fbox\orange{\underline{Question:–}}$

An electric bulb is rated at 200w-100w what is the resistance of 5 such bulbs burn for 4 hours. What is the electrical energy consumed. Calculate the cost if the rate is 50 paise per unit.

$\huge\fbox\orange{\underline{Answer:–}}$

Using, P = $\large{V²}{R}$

we get R = $\large{V²}{P}$

= $\large{(200)²}{100}$

= 400

Energy consumed = P x t

= 100 x 4

= 400 Wh

= 0.4 kWh

Cost at the rate of 50 paise per unit

= Rs (0.50 x 0.4)

= Rs 2

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