Science, asked by wathiduMyrkaur, 1 year ago

An electric bulb is rated at 60W,240V. calculate resistance. If the voltage drops to 192V,calculate the power consumed and the current drawn by the bulb.(assume that resistance of bulb remains unchanged).

Answers

Answered by Lipsa24
128

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Answered by SteffiPaul
14

Given,

Power = 60 W

Voltage = 240 V

Voltage drop = 192 V

To find,

The resistance, power consumed, and the current drawn by the bulb.

Solution,

The resistance, power consumed, and the current drawn by the bulb are 960Ω, 38.4 W, and 0.2 A respectively.

The resistance can be easily calculated by using the formula

R = V²/P

R = 240 * 240/60

R = 960 Ω

Now the Voltage drop is 192 V, the power consumed is

P = V²/R

P = 192 * 192 /960

P = 38.4 W

Now the current is

I = P/V

I = 38.4/192

I = 0.2 A

Hence, the resistance, power consumed, and the current drawn by the bulb are 960Ω, 38.4 W, and 0.2 A respectively.

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