An electric bulb is rated at 60W,240V. calculate resistance. If the voltage drops to 192V,calculate the power consumed and the current drawn by the bulb.(assume that resistance of bulb remains unchanged).
Answers
Answered by
128
so here is your answer
hope it helps you
pls mark brainliest answer
Attachments:
Answered by
14
Given,
Power = 60 W
Voltage = 240 V
Voltage drop = 192 V
To find,
The resistance, power consumed, and the current drawn by the bulb.
Solution,
The resistance, power consumed, and the current drawn by the bulb are 960Ω, 38.4 W, and 0.2 A respectively.
The resistance can be easily calculated by using the formula
R = V²/P
R = 240 * 240/60
R = 960 Ω
Now the Voltage drop is 192 V, the power consumed is
P = V²/R
P = 192 * 192 /960
P = 38.4 W
Now the current is
I = P/V
I = 38.4/192
I = 0.2 A
Hence, the resistance, power consumed, and the current drawn by the bulb are 960Ω, 38.4 W, and 0.2 A respectively.
Similar questions