An electric bulb marked 220 V, 100 W will get fused if it is made to consume 150 W or more. What voltage fluctuation will the bulb withstand?
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The bulb can withstand the voltage fluctuation of 270 V.
Explanation:
- In the question, it is given that the power consumed by the bulb is P and the voltage is V.
- So, the bulb’s resistance is R = V2P = 484 Ω.
- The fluctuation in power is shown as p = 150 W.
- So, the bulb can withstand the voltage fluctuation of 270 V, which can be derived as v = pR = 269.4 V = 270 V.
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