Physics, asked by fyst3577, 9 months ago

Find the thermo-emf developed in a copper-silver thermocouple when the junctions are kept at 0°C and 40°C. Use the data in table (33.1).

Answers

Answered by sachingraveiens
0

Answer:

1600 μ V

Explanation:

Thermo -emf (v) = t²

t = 40° - 0° = 40°

v = 40² = 1600 μ V

Answered by mariospartan
0

In a copper-silver thermocouple, the thermo-emf developed is 1.04 \times 10^{-5} V

Explanation:

The difference in temperature is shown as θ, which is 40 degree Celsius.

Emf, Ecs = acsθ + 12bcsθ2    …(1)

acs =  46.46 μV/°C

bcs = 0.482 μV/°C2

When these values are substituted in the first equation, we get

\text {Ecs}=46.46 \times 40 \times 10^-6+12 \times 0.482 \times(40) 2 \times 10^-6

Thermo-emf = 1.04 \times 10^{-5} V

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