Question

An electric bulb marked 40 W and 200 V, is used in a circuit of supply voltage 100 V. Its power
IS
(1) 10 W
3) 40 W
(2) 20 W
(4) 100 W​

Answer 1

Answer:

40 W

Explanation:

it is given in the question, smh

Answer 2

Answer:

P1 = 40 W

V1 = 200 V

V2= 100 v

we know that,

$\frac{p1}{p2} = \frac{ {(v1)}^{2} }{ {(v2)}^{2} } \\ \frac{40}{p2} = \frac{ {200}^{2} }{ {100}^{2} } \\ p2 = \frac{40}{4} = 10$

Hence, power will be 10 W when voltage is 100V