Question

an electric bulb of resistance 200 ohm draws a current of 1 ampere .calculate Power of bulb,potential differences at its ends and energy in KWh

Answer 1

potential difference. 200 volt

Answer 2

Answer:

We need to find the voltage for getting the answer

Explanation:V=IR

V=200volts

Power = V×I=200

I=200W.

Totally in 5hours the power consumed is 200×5=1000 watt hour = 1kw/h