An electric bulb of resistance 200ohm draw a current of 1 ampere calculate the power , the potential difference at its ends and the energy consumed by the bulb for 5 hours
Answers
Answered by
1
Answer:
Power of the bulb, P = l2R = (1)2 x 200
⇒ P = 200 W
Energy consumed by bulb in 5h in burning
= Power x Time
= 200 x 5
= 1000 Wh
= 1 kWh
Explanation:
Answered by
1
Answer:
Explanation:
Hope it helps!!!
Attachments:
Similar questions