Question

An electric bulb of resistance 200ohm draw a current of 1 ampere calculate the power , the potential difference at its ends and the energy consumed by the bulb for 5 hours

Answer 1

Answer:

Power of the bulb, P = l2R = (1)2 x 200

⇒ P = 200 W

Energy consumed by bulb in 5h in burning

 = Power x Time

= 200 x 5

 = 1000 Wh

= 1 kWh

Explanation:

Answer 2

Answer:

Explanation:

Hope it helps!!!