An electric bulb of resistance 20ohm and a resistance wire of 4ohm are connected in series with a 6v battery. Calculate the total resistance of the circuit and the potential difference across electric bulb and resistance wire?
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total R=24ohm
V=IR
6=I*24
I=0.25
pd of 1 resiatance is 80V
AND 2nd resistane =16v
V=IR
6=I*24
I=0.25
pd of 1 resiatance is 80V
AND 2nd resistane =16v
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