Question

An electric bulb of resistance 480ohm is connected to 230V mains. find the amount of elecrical energy consumsed in 10 minutes​

Answer 1

Answer:

18.36watt

Explanation:

first find p=v*v/r then time converted in hour means 10/60 then e=p *t

Answer 2

$\mathfrak{\large{\underline{\underline{Given:-}}}}$

Resistance of bulb = 480 ohm

Potential difference = 230 v

Time for which it operate = 10 min

=> $\bold{/frac{1}{6}hr}$

$\mathfrak{\large{\underline{\underline{</strong><strong>T</strong><strong>o</strong><strong> </strong><strong>find</strong><strong>:-}}}}$

Electrical energy disipiated= ?

$\mathfrak{\large{\underline{\underline{</strong><strong>S</strong><strong>o</strong><strong>l</strong><strong>u</strong><strong>t</strong><strong>i</strong><strong>o</strong><strong>n</strong><strong>:-}}}}$

The electrical energy consumed is given by = $\boxed{\sf{</strong><strong>P</strong><strong> </strong><strong>=</strong><strong>\frac{ {v}^{2} }{r} </strong><strong> </strong><strong>}}$

Putting the value,

$\implies$ $\bold{</strong><strong>H</strong><strong> </strong><strong>=</strong><strong> </strong><strong>\frac{230 \times 230}{</strong><strong>4</strong><strong>8</strong><strong>0</strong><strong>} </strong><strong> }$

$\implies$ $\bold{<strong>P</strong><strong>=</strong><strong> </strong> 110.208 w}$

$\implies$ $\bold{P<strong> </strong>= 0.110208 kw}$

Now electrical energy consumed is given by :-

$\boxed{\sf{ </strong><strong>E</strong><strong> </strong><strong>=</strong><strong> </strong><strong>P</strong><strong> </strong><strong>×</strong><strong> </strong><strong>T</strong><strong>}}$

$\implies$ $\bold{</strong><strong>E</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong>.</strong><strong>1</strong><strong>1</strong><strong>0</strong><strong>2</strong><strong>0</strong><strong>8</strong><strong> </strong><strong>×</strong><strong> </strong><strong>\</strong><strong>frac</strong><strong> </strong><strong>{</strong><strong>1</strong><strong>}</strong><strong>{</strong><strong>6</strong><strong>}</strong><strong>}$

$\bold{</strong><strong>E</strong><strong> </strong><strong>=</strong><strong>0</strong><strong>.</strong><strong>6</strong><strong>6</strong><strong>3</strong><strong>9</strong><strong> </strong><strong>j</strong><strong>}$