An electric bulb of resistance 500 Ω, draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at its end.
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Explanation:
Given:-
- R = 500 W
- I = 0.4 A,
To find :-
V = ?
Formula used :-
Using V = IR ( Ohm's law )
Solution :-
According to Ohm's Law,
we have V = 0.4 × 500
= 200 V
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