Physics, asked by ItzBrainlyQueen01, 2 months ago

An electric bulb of resistance 500 Ω, draws a current of 0.4 A. Calculate the power of the bulb and the potential difference at its end.​

Answers

Answered by saisubhalaxmi19
1

Explanation:

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Answered by Anonymous
4

Answer:

Hmm...

Maine he kaha tha

Yaad dilane ke liye Thanks

(≧▽≦)

Explanation:

Given:-

  • R = 500 W
  • I = 0.4 A,

To find :-

V = ?

Formula used :-

Using V = IR ( Ohm's law )

Solution :-

According to Ohm's Law,

we have V = 0.4 × 500

= 200 V

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