An electric bulb of resistance 500 ohm draws a current of 0.4A Calculate the power of the bulb and the potential difference at its end. What is the equation to calculate electrical resistivity - Mention its si unit
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r 500ohm ., I 0.4A
p = I*I *R
p = 0.4*0.4 *500
p =80watt
V = IR ohms law
v= 0.4 *500
v=200volts
R=rho*length /area of cross section .
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