Question

An electric bulb of resistance 500 ohm draws a current of 0.4A Calculate the power of the bulb and the potential difference at its end. What is the equation to calculate electrical resistivity - Mention its si unit ​

Answer 1

r 500ohm ., I 0.4A

p = I*I *R

p = 0.4*0.4 *500

p =80watt

V = IR ohms law

v= 0.4 *500

v=200volts

R=rho*length /area of cross section .