An electric bulb of resister 200 ? Draws a current of 1ampere . Calculate the power of the bulb the potential difference at its ends and the energy in kWh consumed burning it for 5h
Answers
Answered by
3
R = 200 ohms.....
I = 1 A...
Now,
P = I^2 * R
= 1^2 * 200
= 200 Watt....
Also,
P = V^2 / R
So, V = √ (PR)
= √ ( 200 * 200)
= 200 V....
Energy
= P * Time
= 200 * 5
= 1000 Watt h...
= 1 kWh....
Hope this helps
I = 1 A...
Now,
P = I^2 * R
= 1^2 * 200
= 200 Watt....
Also,
P = V^2 / R
So, V = √ (PR)
= √ ( 200 * 200)
= 200 V....
Energy
= P * Time
= 200 * 5
= 1000 Watt h...
= 1 kWh....
Hope this helps
Answered by
0
Answer:
1 kwh.
Explanation:
power of the bulb
power of the bulb =I squar x 200
P=200W
energy consumed by bulb in 5 hours in burning.
=power x time
=200x5
=1000wh
=1 kwh.
hope you have understood........
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