an electric bulbu is inscripted as 109w and 110v.if it is connected ti a110v line ,what will be its resistance?
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P = V2/R
If V = 220 V we have
100 W = 2202/R
R = 2202/100 Ω = 484 Ω. This is the resistance of the bulb.
When V = 110 V, power consumed = V2/R = 1102/484 = 25 W.
If V = 220 V we have
100 W = 2202/R
R = 2202/100 Ω = 484 Ω. This is the resistance of the bulb.
When V = 110 V, power consumed = V2/R = 1102/484 = 25 W.
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