an electric cable cost Rs-200.If cable was 5 mtrs longer and each meter of cable cost Rs-2 less the cost of cable would have remained unchanged.represent the above situation in the form of a quadratic equation
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Let the length of piece of clot be x
So, cost of x m cloth = Rs 200 => cost of 1m cloth = Rs 200/x (i)
Now, the piece is 5 m long
New length = (x + 5) m
Also given is that if the cost is reduced by Rs 2 per m, the overall price of the piece of cloth will remain unaffected.
So, the price each m = Rs (200/x+5) - 2 (ii)
Since (i) = (ii) which is given
200/x = (200/x+5) - 2
=> 200/x = (200 - 2x - 10)/x + 5
=> 200/x = 190 - 2x/x + 5
=> 200x + 1000 = 190x - 2x2
=> 2x2 + 10x + 1000 = 0
=> x2 + 5x + 500 = 0
=> x2 - 20x + 25x + 500 = 0
=> x(x - 20) + 25 (x - 20) = 0
=> (x - 20) (x + 25) = 0
=> x = 20 or - 25
But length of the cloth cannot be in negative
So, x ie. length of cloth = 20m
So, cost of x m cloth = Rs 200 => cost of 1m cloth = Rs 200/x (i)
Now, the piece is 5 m long
New length = (x + 5) m
Also given is that if the cost is reduced by Rs 2 per m, the overall price of the piece of cloth will remain unaffected.
So, the price each m = Rs (200/x+5) - 2 (ii)
Since (i) = (ii) which is given
200/x = (200/x+5) - 2
=> 200/x = (200 - 2x - 10)/x + 5
=> 200/x = 190 - 2x/x + 5
=> 200x + 1000 = 190x - 2x2
=> 2x2 + 10x + 1000 = 0
=> x2 + 5x + 500 = 0
=> x2 - 20x + 25x + 500 = 0
=> x(x - 20) + 25 (x - 20) = 0
=> (x - 20) (x + 25) = 0
=> x = 20 or - 25
But length of the cloth cannot be in negative
So, x ie. length of cloth = 20m
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