Question

An electric cell does 5 joules of work in carrying 20 coulomb charge around the closed circuit the potential difference across the cell is
4 Volt 0.25 Volt 100 Volt 2 Volt

Answer 1

Answer:

The electromotive force (e) or e.m.f. is the energy provided by a cell or battery per coulomb of charge passing through it, it is measured in volts (V). It is equal to the potential difference across the terminals of the cell when no current is flowing.

e = E/Q

e = electromotive force in volts, VE = energy in joules, JQ = charge in coulombs, C

In this case, work done = 5 J and amount of charge = 10 C.

Therefore, e = 5/10 = 1/2.

Hence, electromotive force of the cell is 1/2 volt.