Question

An electric charge is formed by +5uc and -5 uC charges at 4mm distance. Calculate the dipole moment and give it's direction.

Answer 1

Hey there!

Answer:


Here charge ( q ) = ± 5 uC


q = ± 5 × $10^{-6}$ C.


Distance ( 2a ) = 4mm


= 4 × $10^{-3}$ m.


Now using the dipole moment formula;


p =( q ).( 2a )


Substituting values;


p =( 5 × $10^{-6}$ ) ( 4 × $10^{-3}$ )


Let the above equation be ( 1 ).


Base same so power should be added.


= $10^{-6}$ × $10^{-3}$


= $10^{-9}$


Put this in equation ( 1 ).


p = 20 × $10^{-9}$ C m.


Hence,
It's direction is from negative to positive.


#Be Brainly.

Answer 2

Answer:

• The Dipole moment (P) is  2 × 10⁻⁸ Cm
• The Direction is from - 5 μC to + 5 μC

Given:

1. Charges given = - 5 μC & + 5 μC
2. Separation between them (2 a) = 4 mm.

Explanation:

$\rule{300}{1.5}$

As the units are not given in S.I units lets first convert them in S.I units.

Now, we Know,

$\displaystyle \dashrightarrow\sf 1\;\mu\;C=10^{-6}\;C\\\\\\\dag\;\bf{Substituting\;the\;values}\\\\\\\dashrightarrow\sf +\;5\;\mu\;C=5\times10^{-6}\;C\\\\\\\text{\underline{Similarly for - 5 \mu C}}\\\\\\\dag\;\bf{Substituting\;the\;values}\\\\\\\dashrightarrow\sf -\;5\;\mu\;C=-\;5\times10^{-6}\;C$

And, for distance

We know,

$\displaystyle \dashrightarrow\sf 1\;mm=10^{\;-3}\;m\\\\\\\dag\; \bf{Substuting\; the \;values}\\\\\\\dashrightarrow\sf 1\times4=4\times10^{\;-3}\;m\\\\\\\dashrightarrow\sf 4\;mm=4\times 10^{\;-3}\;m$

$\rule{300}{1.5}$

$\rule{300}{1.5}$

From the formula we know,

$\large\bigstar\;\boxed{\sf P=(2\;a)\;q}$

Here,

• P Denotes Dipole movement

• ( 2 a ) Denotes the distance between charges

• q Denotes the magnitude of the charge,

Now,

$\boxed{\sf P=(2\;a)\;q}$

Substituting the values,

$\displaystyle\dashrightarrow\sf P=4\times 10^{\;-3}\times5\times 10^{\;-6}\\\\\\\dashrightarrow\sf P=(4\times5)\times 10^{\;-3-6}\\\\\\\dashrightarrow\sf P=20\times 10^{\;-9}\\\\\\\dashrightarrow\sf P=2\times10^{\;-8}\\\\\\\dashrightarrow \large{\underline{\boxed{\red{\sf P=2\times10^{\;-8}\;C\;m}}}}$

∴ The Dipole moment (P) is  2 × 10⁻⁸ Cm.

And, as we know, the direction of dipole is from negative charge to positive charge,

Therefore, here, the direction of the dipole will be from - 5 μC to + 5 μC

.

$\rule{300}{1.5}$