Question

An electric current heater takes a current of 5 A when operated at 200 V, can you calculate the heat developed in the heater in 5 minutes?​

Answer 1

Answer:

300 Kilojoules

Explanation:

Given:

Current taken by the electric heater = i = 5 Amperes

Voltage or potential difference = v = 200 Volts

Time = t = 5 minutes = 300 seconds

To find:

Heat generated in 5 minutes

Heat generated = V×i×t

Heat generated = 200×5×300

Heat generated = 1000×300

Heat generated = 3,00,000J

Heat generated = 300 Kj

The heat generated by the heater with a current of 5 amperes operated at 200 volts for 5 minutes is equal to 300 Kilojoules

Answer 2

GIVEN :-

Current, I = 5 A

Potential difference, V = 200 V

$\boxed{\rule{150}2}$

TO FIND :-

The heat developed in the heater in 5 minutes.

$\boxed{\rule{150}2}$

WE MUST KNOW :-

◙ V = IR (By Ohm's law**)

Where,

• V is the potential difference.

• I is the current.

• R is the resistance.

◙ Heat energy (H.E.) = I²Rt

Where,

• I is the current.

• R is the resistance.

• t is the time taken.

$\boxed{\rule{150}2}$

SOLUTION :-

Using the first formula :-

$\sf{V=IR}\\\\\sf{\longmapsto 200=5\times R}\\\\\sf{\longmapsto R = \dfrac{200}{5} }\\\\\sf{\longmapsto R=40\ \Omega}$

Putting the value of R in the second formula :-

$\sf{H.E.=I^2Rt}\\\\\sf{\longmapsto H.E.=(5)^2\times40\times (5\times60)}\\\sf{(5\ minutes = 5\times60\ secs )}\\\\\sf{\longmapsto H.E.=25\times40\times300}\\\\\sf{\longmapsto H.E.=1000\times300}\\\\\sf{\longmapsto H.E.=300000\ J}\\\\\boxed{\sf{\longmapsto H.E.=300\ kJ}}\:\:\:\: \cdots \mathbf{ANSWER}$

$\rule{200}2$

**Ohm's law is a law that states that the voltage across a resistor is directly proportional to the current flowing through the resistance.