Question

an electric current of 12 amphere flows through a conductor for 15 sec find the amount of charge that flows.

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Answer 1

$\large \bf { \dag Question}$

An electric current of 12 ampere flows through a conductor for 15 sec find the amount of charge that flows.

$\large \bf { \dag Solution }$

Given:

• Current ( I ) = 12 A

• Time ( t ) = 15 s

To find:

• Charge ( Q )

Calculation:

As we know that,

• $\boxed { \large \sf { I = \dfrac{Q}{t}}}$

Where,

• I is current.
• I is current. Q is charge.
• I is current. Q is charge. t is time

Now substitute the values to find amount of charge flows through it ( Q ).

$\large \sf { I = \dfrac{Q}{t}}$

$\large \sf { \leadsto 12 = \dfrac{Q}{15}}$

$\large \sf { \leadsto Q = 15 \times 12 }$

$\large \sf \red { \leadsto Q = 180 C }$

Therefore, amount of charge that flows through it is 180 C.

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More Information :

• The electric current is the flow of charges in a conductor.
• SI unit of electric current is ampere (A).
• Current is measured by ammeter.
• The SI unit of charge is coulomb (C).

Some important formulae:

• $\boxed { \large \sf { I = \dfrac{Q}{t}}}$

• $\boxed { \large \sf { V= \dfrac{W}{Q}}}$

• $\boxed { \large \sf { V = IR}}$ [Ohm's law]

Where,

• I is current and its SI unit is ampere (A).
• Q is charge and its SI unit is coulomb (C).
• t is time and its SI unit is second (s).
• V is potential difference and its SI unit is volt (V).
• W is work done and its SI unit is joule (J).
• R is resistance and its SI unit is Ohm.

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Answer 2

Answer: 180 C.

Explanation:

As, i = Q/t

=> 12 A t = Q

=> Q = 12 A × 15 s = 180 C.

More:

• Q = ± ne and thus, i = ± ne/t.
• Charge in one electron = 1.6 × 10^-6 C.
• Number of electron in 1 C charge = 6.25 × 10^18 p-.
• q∆V = W.
• V = IR. (slope is a straight line determining resistance – only applicable for ohmic conductors.)