Question

An electric current of 3mA flows through a circuit for 30 minutes. The amount of charge flowing through the conductor is​

Answer 1

Given Question:

An electric current of 3A flows through a circuit for 30 minutes. The amount of charge flowing through the conductor is?

Required Solution:

In order to find the charge flowing through it we need to convert minutes to its standard form.

Given:

• I ( Current ) = 3A

• t ( time ) = 30 minutes = 1800 sec

Converting to its SI unit-

→ 30 minutes = ( 30 × 60 )sec

→ 30 minutes = 1800 seconds

To find :

• Q ( Amount of charge )

Calculation:

→ I = Q/t

→ 3A = Q/1800sec

→ Q = 3 × 1800

→ Q = 5400 C

______________________

Additional Information :

• I = Q/t

Where,

➭I is current and its SI unit is Ampere ( A )

➭Q is charge and its SI unit is Coulomb ( C )

➭t is time and its SI unit is seconds ( sec )

• V = W/Q

➭ V is potential difference and its SI unit is volts ( V )

➭W is work done and its SI unit is Joule ( J )

➭Q is charge and its SI unit is Coulomb ( C )

• V = IR ( Ohm's law )

➭ V is potential difference and its SI unit is volts ( V )

➭I is current and its SI unit is Ampere ( A )

➭R is resistance and its SI unit is ohm ( )

• P = W/t

➭P is power and its SI unit is Watt( W )

➭W is work done and its SI unit is Joule ( J )

➭t is time and its SI unit is seconds ( sec ).

_______________________________

Answer 2

$\huge\fcolorbox{black}{lime}{Given}$i

• I ( Current ) = 3A
• t ( time ) = 30 minutes = 1800 sec
• Converting to its SI unit-

• → 30 minutes = ( 30 × 60 )sec

• → 30 minutes = 1800 seconds

$\huge\fcolorbox{black}{lime}{To find}$

• Q ( Amount of charge )

$\huge\fcolorbox{black}{lime}{Solution}$

• → I = Q/t

• → 3A = Q/1800sec

• → Q = 3 × 1800

• → Q = 5400 C