An electric current of 5.0a flows through a 12ohm resistor . What is the rate at which heat energy is produced is the resistor
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3
power = I^2 R
= 5*5*12
=300 Watt
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1
The rate at which Heat Energy is produced i.e.,
Power=i^(2)R
=5^2x12= 25x12= 300W or 300 J/s
Power=i^(2)R
=5^2x12= 25x12= 300W or 300 J/s
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