Question

An electric device draws energy of 500KJ in 1 min. If the resistance of device is 20ohm calculate current flowing through the device

Answer 1

Answer:

I~20.39A

Explanation:

energy, H=500000J

resistance, R=20 ohm

time, t= 1min= 60 seconds

then,

H=I²Rt

or. I²= 5×100000/1200

or. I~ √416

=20.39A

Answer 2

The current flowing through the device is 20.41 A.

Explanation:

It is given that,

Energy drawn by the electric device, $E=500\ kJ=5\times 10^5\ J$

Time, t = 1 min = 60 sec

Resistance of the device, R = 20 ohms

The energy drawn by the electrical device is given by :

$E=I^2Rt$

$I=\sqrt{\dfrac{E}{Rt}}$

$I=\sqrt{\dfrac{5\times 10^5}{20\times 60}}$

I = 20.41 A

So, the current flowing through the device is 20.41 A. Hence, this is the required solution.

Learn more,

Energy drawn

https://brainly.in/question/3669546