Question

An electric dipole is placed at an angle of 30° with an electric field intensity 2 × 105 N/C. It experiences a torque equal to 4 N m. The charge on the dipole, if the dipole length is 2 cm, is​

Answer 1

Answer:

Step 1: Dipole moment of dipole

Given the dipole length l=2 cm=2/100 m

So, the Dipole moment of dipole will be

P=lq =(2/100)q

P=0.02q

Step 2: Torque acting on dipole

τ

=

P

×

E

⇒ τ=PEsinθ

Or, 4 Nm=(0.02q)(2×10

5

N/C)sin30

o

Or, q=200×10

−5

C =2mC

Explanation:

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