Question

find the value of K the equation (4-k )^2x^2 +(2k+4)x+8k+1=0 has coincident root ?also find the roots for all value of K ​

Answer 1

Answer:

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Step-by-step explanation:

The given quadratic will be a perfect square if it has two real and equal roots. To have two real and equal roots the discriminant must be zero.

i.e., b²-4ac=0

or, (2k+4)²-4(4-k)(8k+1)=0

or, 4k²+16k+16-4(32k-8k²+4-k)=0

o², 4k²+16k+16-128k+32k²-16+4k=0

or, 36k²-108k=0

or, 36k(k-3)=0

either 36k=0

or, k=0

or, k-3=0

or, k=3

∴, k=0,3 Ans.

Answer 2

Answer:

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