Question

An electric dipole of length 1 cm is placed with the axis making an angle of 30° to an electric field of strength 10 NC. If it experiences a torque of 6v3 Nm, the potential energy of the dipole is

Answer 1

Potential energy(U) = -pEcostheta - EQ (I)

We know torque= p E then p=torque /E

By Putting in EQ (I)

U= (-) torque × cos theta

So U= 6√3 × 1/2

U=>-3√3 joules

Answer 2

Explanation:

Torque,

<br> Here, l is the length of the dipole, q-is the charge and E is the electric field. <br>

<br> Dividing (ii) by (i): <br>

<br>