World Languages, asked by riyanghori8025, 1 year ago

An electric dipole of moment p is lying along a uniform electric field
e.the work done in rotating the dipole by 90° is

Answers

Answered by gentalwolf
39
work done=p.E(cos●2-cos●1)
so p.E(cos90°-cos0°)
w=pE
Answered by jitushashi143
18

Answer:

Work Done (W) =pE

Explanation:

The magnitude of the electric dipole is p

The magnitude of electric field is E

Initially dipole makes an angle of \theta_{1}=90^o and finally it makes \theta_{2}=0^{o} with electric field

The initial potential energy of the dipole is

U_{i}=pE \cos \theta_{1}\\U_{i}=pE\cos 90\\U_{i}=pE

The final potential energy of the dipole is

U_{f}=pE\cos \theta_{2}\\U_{f}=pE\cos  0\\U_{f}=0

We know that change in potential energy is work done

So,

W=\Delta U \\W=U_{f}-U_{i}\\W=pE-0\\W=pE

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