Question

An electric dipole of two opposite charges of same magnitude 2µC separated by 4cm , is

placed in an electric field of 3 x10 4

V/m ,at an angle of 30◦ .Calculate the torque

experienced by it​

Answer 1

Answer:

Given data,

Charges(q)=2×10

−6

C,

Distance(d)=3cm=3×10

−2

m

electric field(E)=2×10

5

N/C.

Torque(τ)=?

We know that

Torque(τ) to be measured

Torque=charge×distance×Electric field

Torque(τ)=(2×10

−6

)×(3×10

−2

)×(2×10

5

)

=12×10

−3

Nm

Explanation:

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