An electric fan runs from 220V mains.The current flowing through it is 0.6A at what rate is electrical energy transferred by the fan?how much energy is transformed in two minutes?
Answers
An electric fan runs from 220V mains. The current flowing through it is 0.6 A .
To find : rate of electrical energy transferred by the fan and also energy is transferred in two minutes.
Solution : voltage supplied to electric fan, V = 220 volts.
current flowing through it, I = 0.6 A
rate of electrical energy transferred by the fan, P = VI
= 220 volts × 0.6 A
= 132 J/s
Therefore 132 J of electrical energy is transferred by the fan per second.
Energy transferred in two minutes = 132 J/s × 2 minutes
= 132 × 2 × 60 J
= 15840 J = 15.84 kJ
15.84 kJ energy is transferred in two minutes by the fan.
Given,
- An electric fan runs from 220V mains.
- The current flowing through it is 0.6A
To Find:-
- Rate of electrical energy transferred by the fan.
- How much energy is transformed in 2min.
Calculation:-
Voltage (V) = 220V
Current flowing (I) = 0.6A
Rate of electrical energy
transferred by the fan = P=VI
Substituting the given values in formula
=220voltes×0.6A
=132J/s
So,
132J of energy transferred by the fan oer second.
Energy transferred in 2min = 132J/s×2min
=132×2×60
=15840 J
= 15.84 KJ.