Question

An electric geyser consumes electricity at the rate of 1000W. If the potential difference through
the electric circuit is 250 V, find the resistance offered by geyser and electric current through the
circuit​

Answer 1

 

1000 W = 250 V × I

 

I = 1000 V ÷ 250 V = 4 A

R = 250 V ÷ 4 A =62.5Ω

Answer 2

Answer:

The required resistance is 62.5 ohm.

Explanation:

Given Data :

The rate of consuming electricity = Power(p) = 1000 W

Potential Difference (v) = 250 V

Formula to be used :

$p = \frac{ {v}^{2} }{r} \\ r = \frac{ {v}^{2} }{r}$

Obtaining Results:

$r \: = \frac{ {250}^{2} }{1000} = 62.5$

Hence, the required resistance is 62.5 Ohm.

Definition of Power :

• The quantity of energy transferred or transformed per unit of time is known as power.
• It is expressible as W/t, where W is the quantity of work completed or energy transferred, and t is the time interval.
• A high-powered motor can complete a given amount of work quickly or a low-powered motor can accomplish it slowly.
• Power (P) is defined as Work divided by time (W/t). In honour of Scottish inventor James Watt, the Watt (W) serves as the SI unit of power.

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