Question

Hello everyone ❤❤

I have a question ❗❗

➡ The length of a rectangular field is increased by 50% and the breadth is decreased by 50% to from a new rectangular field. what will be the change in area of the new field?

plzz solve this !!!

Answer 1

$\mathfrak{ \huge{\star \:{solution \:\star}}}$

$\bold{{\textitlet the lenght and breadth of the rectanglar}}\\ \bold{ \textit{field be l \: m and b \: m respectively.}}$

Then,

$\bold{ \: Area \: = (l \times b) {m}^{2} }$

$Length \: of \: the \: new \: field \\ = l + \frac{50}{100} \times l = l + \frac{1}{2} l = (\frac{3}{2} l)m \\ \\ Breadth \: of \: the \: new \: field \: \\ = b - \frac{50}{100 } \times b = b - \frac{1}{2} b = ( \frac{1}{2} b)m \\ \\ Area \: of \: the \: new \: rectangular \: field \\ = (\frac{3}{2} l \times \frac{1}{2} b) \: {m}^{2} = (\frac{3}{4} l \times b) {m}^{2} \\ \\ Change \: in \: area \: of \: the \: new \: field \: \\ = ( \frac{Diff. \: in \: are}{Original \: area } \times 100) \\ \\ = ( \frac{(lb) - ( \frac{3}{4} lb)}{lb} \times 100 ) \\ \\ = ( \frac{ \frac{1}{4} lb}{lb} \times 100 ) \\ \\ = ( \frac{1}{4} \times 100) \\ \\ = 25$

$\bold{ \mathfrak{Glad \: help \: you!!!}}$
$\mathfrak{it \: helps \: uh!!!}$
$\huge{ \mathfrak{thanks}}$

Answer 2

Hey mate ^_^

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Answer:
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Let length of rectangle is L and breadth of rectangle is B

Area of rectangle = LB

a/c to question,

Length increased by 50% e.g.,
New length of rectangle is L + L/2 = 3L/2

Breadth decreased by 50% e.g.,
New breadth of rectangle is B - B/2 = B/2

Now,
New area of rectangle is 3L/2 * B/2 = 3LB/4 

Hence,

% change in area = ( final area - initial area ) / initial area * 100
                                       
= (3LB/4 -LB)/LB *100 = -25%

Here,

Negative sign shows area decreased by 25 %

#Be Brainly❤️