Question

An electric heater can offer a maximum resistance of 50 ohm when a 3 amber of current flows through it for a minute. what is the maximum amount of heat produced by the heater

Answer 1

☞Given

An electric heater can offer a maximum resistance of 50 ohm when a 3 amper of current flows through it for a minute.

☞To find

what is the maximum amount of heat produced by the heater

☞Solution

✞ According to the joules of heating

This law can be stated as the amount of heat produced in a conductor is

✰ Directly proportional to the square of current flowing through it .

✰ Directly proportional to resistance of a conductor.

✰Directly proportional to the time .

So, H = I²Rt

where ,

• H = heat
• I = current
• R = resistance
• t = time

✛ According to the question

• R = 50ohm
• I = 3A
• t = 1min = 60sec
• H = ??

✛ Applying Formula

→ H = l²Rt

→ H = (3)² × 50 × 60

→ H = 9 × 3000

→ H = 27000 Joules

Hence, the maximum amount of heat produced by heater is 27000 Joules

Answer 2

To know the answer for this question we need to know a small formula used for this sum, That is $\: \: \:\:\: \: \circ \: \underline{\boxed{\red{\scriptsize{ \sf H\:=\:I²Rt}}}}$

Where,

• H = Heat
• I = Current
• R = Resistance and
• t = Time

So now we can start doing the Problem !

= H = I²Rt

= 3² × 50 × 60 ( 3 Amber, 50 ohm and 60 minutes )

= 450 × 60 or 9 × 3000

= 27, 000 J ( Joules )

∴ The maximum amount of heat produced by the heater is 27, 000 J .