An electric heater has 3 kw, 220 v, stamped on it. Find values of the following–
(a) Electric current
(b) Resistance of the heater
(c) Cost of electricity if unit cost is Rs. 1.50/kwh and heater is used for 10 hours
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P=VI
3000=220×I
I= 300/22
I = 13.63 amp
R=V/I
R= 220/13.63
R=16.133 ohm
rate = p×t×₹
= ₹3×10×60×1.5
=₹2700.
3000=220×I
I= 300/22
I = 13.63 amp
R=V/I
R= 220/13.63
R=16.133 ohm
rate = p×t×₹
= ₹3×10×60×1.5
=₹2700.
Answered by
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Okay Given data's are
P- 3000 W
V-220 V
(a)
P=VI
I=P/V
=3000/220
I=13.64 A
(b)
Resistance of the heater
R=V*V/P
=220*220/3000
R=16.13 ohm.
(c)
Unit consumer= P*t
=3*10
=30kWh
now unit cost is 1.5/kWh rupees
so 30kWh cost 30*1.5=45/- rupees.
P- 3000 W
V-220 V
(a)
P=VI
I=P/V
=3000/220
I=13.64 A
(b)
Resistance of the heater
R=V*V/P
=220*220/3000
R=16.13 ohm.
(c)
Unit consumer= P*t
=3*10
=30kWh
now unit cost is 1.5/kWh rupees
so 30kWh cost 30*1.5=45/- rupees.
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