Physics, asked by bhallajee10, 1 year ago

An electric heater is connected to the 230V main supply .A current of 8A flows through it.
A) how much charge flows around the circuit each second.
B) how much energy is transferred to the heater each second.

Answers

Answered by Anonymous
203
A) Charge flowing each second = Current = 8 coulombs

B) Energy flowing each second = Power = Voltage × Current = 230 × 8 = 1840 J
Answered by lidaralbany
134

Answer:

The charge flows around the circuit each second is 8 C and the energy is transferred to heater each second is 1840 J

Explanation:

Given that,

Voltage = 230 V

Current I= 8 A

(A). The charge flows around the circuit each second

The charge is the product of current and time.

 q= i\times t

q= 8 A-s=8 C

(B). The energy is transferred to the heater each second

The energy is the product of the power and time.

The power is the product of voltage and current.

P=V\times I

P=230\times8

P=1840\ Watt

The energy is

E= P\times t

E= 1840\times 1

E= 1840\ J

Hence, The charge flows around the circuit each second is 8 C and the energy is transferred to heater each second is 1840 J

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