Question

An electric heater is rated 3kw. calculate
the energy consumed by heater in I month
if daily run 2 hour
​

Answer 1

Answer:6.48×10^5 KiloJoule

Step-by-step explanation:

If a heater is rated 3kw it loses 3 kw power in 1 hour.

If in 1 hour lose 3kw power

then daily 2 hour loses 2×3=6kw power

In 1 month=30 days loses 30×6=180Kw

And we know that 1Kw=3.6×10^6Joule

Then 180Kw=180×3.6×10^6 Joule

=6.48×10^8 Joule

=6.48×10^5 KiloJoule