Question

An electric heater of 3 kw is used for 10 hours express your answer in joule

Answer 1

Power of electric heater = 3 KW = 3000W
Time it used = 10 hours = 36000 s

Work done = 3000*36000 = 108000000 J
 
The work done here = 108000000 J

Answer 2

Power = 3 kW = 3000 W

Time = 10 h = 36000 s

${ \blue{ \bf{ P=E/T }}}$

${ \blue{ \bf{ E=P×T }}}$

E=3000×36000

E = 108000000J

${ \blue{ \bf{ In\: Joule \: = 1.08×10⁸J }}}$

1kWh = 3600000J

${ \blue{ \bf{ So, }}}$

108000000/3600000

${ \blue{ \bf{ In \: kWh \: =30kWh \: Ans }}}$