An electric heater of resistance 5 22 is connected to an electric source. If a current of 6 Aflows through the heater, then find the amount of heat produced in 5 minutes.
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Explanation:
Current, I= 6 A
Risistance, R = 522 ohm
Time, t= 5min
= 5×60 sec
= 300 sec
H= I^2Rt
= 6×6×522×300.
=36×522×300
=5637600 joule
=5637600/1000 kilojoule
=5637.6 kilojoule
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