an electric heater of resistance 500 ohms is connected to a main supply for 30 minutes. if 15A current flows through the filament of heater, then calculate the heat energy produced in the heater
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Power = I^2R
=> " = 15*15*500 W
=> Power = 1125 W
Energy = 1125 W * 0.5 h = 562.5 W h
or say Energy = 2.025 * 10^6 J
=> " = 15*15*500 W
=> Power = 1125 W
Energy = 1125 W * 0.5 h = 562.5 W h
or say Energy = 2.025 * 10^6 J
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We have to calculate the heat energy produced in the heater when the electric heater is of resistance 500 ohms.
And the time of main supply is 30 minutes.
The given Current = I = 15A
Time = 30 minutes.
Converting this time into seconds = 30 × 60 = 1800 seconds.
We know the formula to find heat energy, that is :
H = I²Rt
So ,
H = (15)²×500×1800
= 202,500,000 J = 2.025 × 10^8
The required heat energy produced in the heater is 2.025 × 10^8 J
And the time of main supply is 30 minutes.
The given Current = I = 15A
Time = 30 minutes.
Converting this time into seconds = 30 × 60 = 1800 seconds.
We know the formula to find heat energy, that is :
H = I²Rt
So ,
H = (15)²×500×1800
= 202,500,000 J = 2.025 × 10^8
The required heat energy produced in the heater is 2.025 × 10^8 J
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