Question

An electric heater of resistance 6 ohm takes a current of 13 A from the mains supply line. Calculate the rate at which heat is developed in the heater?​

Answer 1

Answer:

1014 watt

Explanation:

p= I2R,

p=?

I=13A

R=6ohm

find R=?

P=13×13×6

=1014watt ans