Question

An electric heater of resistance 8 ohm draws 15 a from the service mains 2 hours. Calculate the rate at which heat is developed in the heater.

Answer 1

Answer:

This is you answer

Hope it helps

Answer 2

Answer:

3600joules

Explanation:

h=i^2*r*t

=(15)^2*8*2

=(15)^2*16

=(15)^2*(4)^2

=(15*4)^2

=(60)^2

=3600joules