Question

an electric heater of resistance 8 ohm draws 15 a from the service mains 2 hour . calculate the rate at which heat is developed in the heater?

Answer 1

Here Given that Resistance of the electric heater (R) = 8 Ω

Current drawn (I) = 15 A

We know that P = I2R

                         = 15×15×8

                          = 1800w or J/s

∴ Heat is produced by the heater at the rate of 1800 J/s.

Answer 2

hello@

here is u r answer@

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given :-

I = 15A

R = 8 ohm.

t = 2h = 2×60 ×60s

heat develop ,H = I^2 Rt

= (15)2 × 8 × 2 × 60 ×60 j.

rate at which heat is developed or power.

= heat develop / time taken

15×15×8×2×60×60 / 2×60× 60


= 1800 W.


I hope help u