Question

An electric heater of resistance 8ohms draws 15A from the service
mains in 2 hours. Calculate the rate at which heat is developed in
the heater.
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Answer 1

Here Is Your Ans

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➡H = I^2 × R × T

➡H = 15^2 × 8 × 2

➡H = 225 × 16

➡H = 3600 joule

Hence , 3600 joule heat is developed in the heater

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Answer 2

Answer:

1800 j/s

Explanation:

Heat developed in the heater is given by H = I2Rt Where, I = 15 A, R = 8 Ω and time t = 2 hours The rate at which heat is developed is given by