an electric heater supplies heat to system at a rate of 100W. If system performs work at rate of 75 joules per second, at what rate is the internal energy increasing
Answers
Answered by
118
solution
_________
∆U = 100W = 100J/s
∆W = 75J/s
increase in internal energy, ∆U = ?
∆Q = ∆U + ∆W
•°• ∆U = ∆Q - ∆W = 100 - 75
= 25J/s
___________
_________
∆U = 100W = 100J/s
∆W = 75J/s
increase in internal energy, ∆U = ?
∆Q = ∆U + ∆W
•°• ∆U = ∆Q - ∆W = 100 - 75
= 25J/s
___________
Answered by
20
♥Hola mate♥
Answer:-
25J/S joules
Answer:-
25J/S joules
Similar questions