an electric iron consumed energy ate a rate of 500 W when the heating is at the maximum rate and voltage applied in 220 V. find the current drawn and the resistance of electric iron
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Answer:
Power =VI=
R
V
2
, Where V is voltage, I is current , R is resistance.
First case,
Power=880W ⇒880=220×I ⇒I=4A
⇒880=
R
220
2
⇒R=55Ω
Second Case,
Power =440W=220×I ⇒I=2A
⇒440=
R
220
2
⇒R=110Ω
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