Question

An electric iron consumer’s energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum,the voltage is 220 V. What are the current and the resistance in each case?.

Answer 1

Answer:

current in first case:-

as ,

P=VI

840/220=42/11ampere

as V=IR ,

220÷42/11= 121/21ohm's

in second case,

360/220=12/11 ampere.

220÷12/11=605/3 ohm's..

Answer 2

Answer:

Pmax = 840 W

Pmin = 360 W

voltage remains same for both cases.

P = V² / R  = V I

I = 840/220 = 3.82 A  at the maximum heating state

   = 260/220 = 1.18 A at the minimum heating state

R = 220 * 220 / 840 =   57.62  Ohms  at the maximum power or heating

   = 220 * 220 / 360 =  134.44 Ohms at the minimum power or heating

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