an electric iron draws a current of 0.5 amperes when voltage is 200V calculate the amount of charge flowing through it in one hour
Answers
Answered by
31
current I=0.5A
voltage V =200v
time t=1h=3600sec
the rate of flow of changes is termed as current
I=Q/t
Q=It
Q=0.5x3600
Q=1800C
voltage V =200v
time t=1h=3600sec
the rate of flow of changes is termed as current
I=Q/t
Q=It
Q=0.5x3600
Q=1800C
Answered by
10
Answer:
Explanation: Given:- I = 0.5
Q = ?
T = 1h
T= 1h
= 60X60
= 3600 sec
We Know That
I=Q/T
0.5=Q/3600
Q= 0.5X3600
= 1800C
Therefore,
Amount of change flowing in one hour is 1800C
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