Question

an electric iron draws a current of 0.5 amperes when voltage is 200V calculate the amount of charge flowing through it in one hour

Answer 1

current I=0.5A
voltage V =200v
time t=1h=3600sec
the rate of flow of changes is termed as current
I=Q/t
Q=It
Q=0.5x3600
Q=1800C

Answer 2

Answer:

Explanation: Given:- I = 0.5

Q = ?

T = 1h

T= 1h

= 60X60

= 3600 sec

We Know That

I=Q/T

0.5=Q/3600

Q= 0.5X3600

= 1800C

Therefore,

Amount of change flowing in one hour is 1800C